[NSRCA-dist7] Clarification on FAI maneuver 1

[Scott C]

Good, sounds like we all agree.

sc
  ----- Original Message ----- 
  From: Derek Koopowitz 
  To: 'CA, AZ, HI, NV, UT' 
  Sent: Friday, May 02, 2008 9:30 AM
  Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1


  There is NO straight inverted flight before the push.



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  From: nsrca-dist7-bounces at lists.nsrca.org [mailto:nsrca-dist7-bounces at lists.nsrca.org] On Behalf Of Scott C
  Sent: Friday, May 02, 2008 9:03 AM
  To: CA, AZ, HI, NV, UT
  Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1


  My reading of this is.. you do a 2 of 4 point roll. This means FLY INVERTED the same length of line as the KE portion. So, are you saying there IS inverted flight, or there is not inverted flight as the 2nd point of the 2 of 4?

  I do not believe there should be any inverted flight, or very little (a few feet), as it starts the outside radius of the 1/2 outside loop. 

  How do you read this?

  sc
    ----- Original Message ----- 
    From: Derek Koopowitz 
    To: 'CA, AZ, HI, NV, UT' 
    Sent: Friday, May 02, 2008 7:44 AM
    Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1


    The official description from the rule book is:

    Reverse Split S and Split S Combo, 2/4-pt roll first, full roll second, inverted exit.

    From upright, perform 2 points of a 4-pt roll, and push immediately to a half outside loop.  Perform a full
    roll, followed immediately by a half outside loop, to exit inverted.

    Judging notes:
    1.  The outside half loops must follow immediately after the 2/4-pt roll and roll.
    2.  The length of the upper horizontal line (including roll) is equal to the diameter of the half loops.  The geometric shape is that of a Double Immelmann.

    -----Original Message-----
    From: nsrca-dist7-bounces at lists.nsrca.org [mailto:nsrca-dist7-bounces at lists.nsrca.org] On Behalf Of Budd Engineering
    Sent: Friday, May 02, 2008 6:58 AM
    To: CA, AZ, HI, NV, UT
    Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1

    Hi all,

    I'm pretty sure the following isn't correct (IIRC Jason and the Canucks corrected me on it at Phoenix), because the maneuver isn't a Double Immelman.  It's probably worth checking on though.

    "the lenght of the upper horizontal line (including roll) is equal tothe diameter of the half loops.
    The geometric shape is that of of a Double Immelmann."

    Thx, Jerry

    Budd Engineering
    jerry at buddengineering.com
    http://www.buddengineering.com


    On May 1, 2008, at 4:49 PM, Robert Gillespie wrote:

    > the lenght of the upper horizontal line (including roll) is equal
    > tothe diameter of the half loops.
    > The geometric shape is that of of a Double Immelmann.

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