[NSRCA-dist7] Clarification on FAI maneuver 1

[Derek Koopowitz]

There is NO straight inverted flight before the push.

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From: nsrca-dist7-bounces at lists.nsrca.org
[mailto:nsrca-dist7-bounces at lists.nsrca.org] On Behalf Of Scott C
Sent: Friday, May 02, 2008 9:03 AM
To: CA, AZ, HI, NV, UT
Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1


My reading of this is.. you do a 2 of 4 point roll. This means FLY INVERTED
the same length of line as the KE portion. So, are you saying there IS
inverted flight, or there is not inverted flight as the 2nd point of the 2
of 4?
 
I do not believe there should be any inverted flight, or very little (a few
feet), as it starts the outside radius of the 1/2 outside loop. 
 
How do you read this?
 
sc

----- Original Message ----- 
From: Derek Koopowitz <mailto:derekkoopowitz at sbcglobal.net>  
To: 'CA, AZ, HI, NV, UT' <mailto:nsrca-dist7 at lists.nsrca.org>  
Sent: Friday, May 02, 2008 7:44 AM
Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1


The official description from the rule book is:

Reverse Split S and Split S Combo, 2/4-pt roll first, full roll second,
inverted exit.

>From upright, perform 2 points of a 4-pt roll, and push immediately to a
half outside loop.  Perform a full
roll, followed immediately by a half outside loop, to exit inverted.

Judging notes:
1.  The outside half loops must follow immediately after the 2/4-pt roll and
roll.
2.  The length of the upper horizontal line (including roll) is equal to the
diameter of the half loops.  The geometric shape is that of a Double
Immelmann.

-----Original Message-----
From: nsrca-dist7-bounces at lists.nsrca.org
[mailto:nsrca-dist7-bounces at lists.nsrca.org] On Behalf Of Budd Engineering
Sent: Friday, May 02, 2008 6:58 AM
To: CA, AZ, HI, NV, UT
Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver 1

Hi all,

I'm pretty sure the following isn't correct (IIRC Jason and the Canucks
corrected me on it at Phoenix), because the maneuver isn't a Double
Immelman.  It's probably worth checking on though.

"the lenght of the upper horizontal line (including roll) is equal tothe
diameter of the half loops.
The geometric shape is that of of a Double Immelmann."

Thx, Jerry

Budd Engineering
jerry at buddengineering.com
http://www.buddengineering.com


On May 1, 2008, at 4:49 PM, Robert Gillespie wrote:

> the lenght of the upper horizontal line (including roll) is equal
> tothe diameter of the half loops.
> The geometric shape is that of of a Double Immelmann.

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