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<DIV dir=ltr align=left><SPAN class=265143016-02052008><FONT face=Arial
color=#0000ff size=2>There is NO straight inverted flight before the
push.</FONT></SPAN></DIV><BR>
<DIV class=OutlookMessageHeader lang=en-us dir=ltr align=left>
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<FONT face=Tahoma size=2><B>From:</B> nsrca-dist7-bounces@lists.nsrca.org
[mailto:nsrca-dist7-bounces@lists.nsrca.org] <B>On Behalf Of </B>Scott
C<BR><B>Sent:</B> Friday, May 02, 2008 9:03 AM<BR><B>To:</B> CA, AZ, HI, NV,
UT<BR><B>Subject:</B> Re: [NSRCA-dist7] Clarification on FAI maneuver
1<BR></FONT><BR></DIV>
<DIV></DIV>
<DIV><FONT face=Tahoma>My reading of this is.. you do a 2 of 4 point roll. This
means FLY INVERTED the same length of line as the KE portion. So, are you saying
there IS inverted flight, or there is not inverted flight as the 2nd point of
the 2 of 4?</FONT></DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV><FONT face=Tahoma>I do not believe there should be any inverted flight, or
very little (a few feet), as it starts the outside radius of the 1/2
outside loop. </FONT></DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV><FONT face=Tahoma>How do you read this?</FONT></DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV><FONT face=Tahoma>sc</FONT></DIV>
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=derekkoopowitz@sbcglobal.net
href="mailto:derekkoopowitz@sbcglobal.net">Derek Koopowitz</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A title=nsrca-dist7@lists.nsrca.org
href="mailto:nsrca-dist7@lists.nsrca.org">'CA, AZ, HI, NV, UT'</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Friday, May 02, 2008 7:44 AM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [NSRCA-dist7] Clarification
on FAI maneuver 1</DIV>
<DIV><BR></DIV><!-- Converted from text/plain format -->
<P><FONT size=2><FONT face=Tahoma size=3>The official description from the
rule book is:<BR><BR>Reverse Split S and Split S Combo, 2/4-pt roll first,
full roll second, inverted exit.<BR><BR>From upright, perform 2 points of a
4-pt roll, and push immediately to a half outside loop. Perform a
full<BR>roll, followed immediately by a half outside loop, to exit
inverted.</FONT></FONT></P>
<DIV><FONT size=2><FONT face=Tahoma size=3>Judging notes:<BR>1. The
outside half loops must follow immediately after the 2/4-pt roll and
roll.</FONT></FONT></DIV>
<DIV><FONT size=2><FONT face=Tahoma size=3>2. The length of the upper
horizontal line (including roll) is equal to the diameter of the half
loops. The geometric shape is that of a Double
Immelmann.<BR><BR></FONT>-----Original Message-----<BR>From:
nsrca-dist7-bounces@lists.nsrca.org [<A
href="mailto:nsrca-dist7-bounces@lists.nsrca.org">mailto:nsrca-dist7-bounces@lists.nsrca.org</A>]
On Behalf Of Budd Engineering<BR>Sent: Friday, May 02, 2008 6:58 AM<BR>To: CA,
AZ, HI, NV, UT<BR>Subject: Re: [NSRCA-dist7] Clarification on FAI maneuver
1<BR><BR>Hi all,<BR><BR>I'm pretty sure the following isn't correct (IIRC
Jason and the Canucks corrected me on it at Phoenix), because the maneuver
isn't a Double Immelman. It's probably worth checking on
though.<BR><BR>"the lenght of the upper horizontal line (including roll) is
equal tothe diameter of the half loops.<BR>The geometric shape is that of of a
Double Immelmann."<BR><BR>Thx, Jerry<BR><BR>Budd
Engineering<BR>jerry@buddengineering.com<BR><A
href="http://www.buddengineering.com">http://www.buddengineering.com</A><BR><BR><BR>On
May 1, 2008, at 4:49 PM, Robert Gillespie wrote:<BR><BR>> the lenght of the
upper horizontal line (including roll) is equal<BR>> tothe diameter of the
half loops.<BR>> The geometric shape is that of of a Double
Immelmann.<BR><BR>_______________________________________________<BR>NSRCA-dist7
mailing list<BR>NSRCA-dist7@lists.nsrca.org<BR><A
href="http://lists.nsrca.org/mailman/listinfo/nsrca-dist7">http://lists.nsrca.org/mailman/listinfo/nsrca-dist7</A></FONT>
</DIV>
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