[NSRCA-discussion] Electrical Help

[Larry & Eileen Fitch]

In Idaho Falls, Idaho, in December and January, you can push with a rope.

Just say'n
Larry Fitch
  ----- Original Message ----- 
  From: Keith Hoard 
  To: General pattern discussion 
  Sent: Wednesday, October 23, 2013 10:47 AM
  Subject: Re: [NSRCA-discussion] Electrical Help


  And you can't push with a rope.  

  Sent from my iPhone

  On Oct 23, 2013, at 12:16, "Patrick Harris" <harris7148 at gmail.com> wrote:


    The formula for voltage drop is: Voltage Drop = I times R


    I = current in Amps
    R = Resistance of the conductor in Ohms


    So for any given length of wire, the resistance will increase as the size of the conductor deceases and the voltage will drop for any given level of draw (amps). 


    In other words in your case, lets say you put a load on the circuit of a given length that draws x amount of amps, you will see a voltage drop as the conductor size reduces (resistance increases). 


    As the formula is stated, if you have no "current" draw, you will have no voltage drop, but why would you have a circuit if you didn't put a load on it?  In other words the voltage will drop.


    This will calculate it for you.


    http://www.calculator.net/voltage-drop-calculator.html




    On Wed, Oct 23, 2013 at 3:42 AM, Del R <drykert2 at rochester.rr.com> wrote:

      Ron .. I think you are referring to current or amperage.. Voltage won't show a drop.. 14 gauge is a no no.. except for lighting basically.. Low current drain. 

          Del
        ----- Original Message ----- 
        From: Ron Hansen 
        To: NSCRA Discussion List 
        Sent: Tuesday, October 22, 2013 10:35 PM
        Subject: [NSRCA-discussion] Electrical Help


        For a 120 VAC system, can anyone tell me what the voltage drop will be over a give length of 10 gauge, 12 gauge and 14 gauge copper wiring?



        Thanks



        Ron



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