[NSRCA-discussion] Electrical Help

Phil S. chuenkan at comcast.net
Wed Oct 23 12:09:58 AKDT 2013


And November, and February, and March, and April, and...lol

Phil Spelt, KCRC Emeritus, Past President
AMA 1294 Scientific Leader Member
SPA L-18, Board Member
(865)435-1476v, (865)604-0541c


On 10/23/2013 3:19 PM, Larry & Eileen Fitch wrote:
> In Idaho Falls, Idaho, in December and January, you can push with a rope.
> Just say'n
> Larry Fitch
>
>     ----- Original Message -----
>     *From:* Keith Hoard <mailto:klhoard at hotmail.com>
>     *To:* General pattern discussion
>     <mailto:nsrca-discussion at lists.nsrca.org>
>     *Sent:* Wednesday, October 23, 2013 10:47 AM
>     *Subject:* Re: [NSRCA-discussion] Electrical Help
>
>     And you can't push with a rope.
>
>     Sent from my iPhone
>
>     On Oct 23, 2013, at 12:16, "Patrick Harris" <harris7148 at gmail.com
>     <mailto:harris7148 at gmail.com>> wrote:
>
>>     The formula for voltage drop is: Voltage Drop = I times R
>>
>>     I = current in Amps
>>     R = Resistance of the conductor in Ohms
>>
>>     So for any given length of wire, the resistance will increase as
>>     the size of the conductor deceases and the voltage will drop for
>>     any given level of draw (amps).
>>
>>     In other words in your case, lets say you put a load on the
>>     circuit of a given length that draws x amount of amps, you will
>>     see a voltage drop as the conductor size reduces (resistance
>>     increases).
>>
>>     As the formula is stated, if you have no "current" draw, you will
>>     have no voltage drop, but why would you have a circuit if you
>>     didn't put a load on it?  In other words the voltage will drop.
>>
>>     This will calculate it for you.
>>
>>     http://www.calculator.net/voltage-drop-calculator.html
>>
>>
>>     On Wed, Oct 23, 2013 at 3:42 AM, Del R <drykert2 at rochester.rr.com
>>     <mailto:drykert2 at rochester.rr.com>> wrote:
>>
>>         Ron .. I think you are referring to current or amperage..
>>         Voltage won't show a drop.. 14 gauge is a no no.. except for
>>         lighting basically.. Low current drain.
>>             Del
>>
>>             ----- Original Message -----
>>             *From:* Ron Hansen <mailto:rcpilot at wowway.com>
>>             *To:* NSCRA Discussion List
>>             <mailto:nsrca-discussion at lists.nsrca.org>
>>             *Sent:* Tuesday, October 22, 2013 10:35 PM
>>             *Subject:* [NSRCA-discussion] Electrical Help
>>
>>             For a 120 VAC system, can anyone tell me what the voltage
>>             drop will be over a give length of 10 gauge, 12 gauge and
>>             14 gauge copper wiring?
>>
>>             Thanks
>>
>>             Ron
>>
>>
>>
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