[NSRCA-discussion] LIPO Question

[Bob Kane]

Without doing much math, from your note below Brand B is roughly twice the resistance of Brand A, so it will run hotter if run at the same current.


If you want to do the math, the simple way is to measure the current at full throttle, then plug the number into this equation:
Power = MaxCurrent * 1000 * Cell Resistance (in Milliohms)   This will tell you how much power is being absorbed by the packs. More power absorbed  is bad, less power absorbed is good.

Converting power absorbed into temperature rise over time is more complicated.
 

Bob Kane
getterflash at yahoo.com


________________________________
 From: J N Hiller <jnhiller at earthlink.net>
To: NSRCA Mailing List <nsrca-discussion at lists.nsrca.org> 
Sent: Friday, July 26, 2013 3:30 PM
Subject: [NSRCA-discussion] LIPO Question
 

HELP!

I'm trying to understand battery heat gained from internal cell resistance.
Total resistance of brand A = 13, Brand B = 28 (Twin 5S 5000 packs - new -
unused).

Can someone point me to a formula?

Thanks
Jim Hiller

_______________________________________________
NSRCA-discussion mailing list
NSRCA-discussion at lists.nsrca.org
http://lists.nsrca.org/mailman/listinfo/nsrca-discussion
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.nsrca.org/pipermail/nsrca-discussion/attachments/20130726/13126e82/attachment.html>