<html><body><div style="color:#000; background-color:#fff; font-family:times new roman, new york, times, serif;font-size:12pt"><div><span style="background-color: transparent; font-size: 12pt;">Without doing much math, from your note below Brand B is roughly twice the resistance of Brand A, so it will run hotter if run at the same current.</span><br></div><div style="color: rgb(0, 0, 0); font-size: 16px; font-family: 'times new roman', 'new york', times, serif; background-color: transparent; font-style: normal;"><br></div><div style="color: rgb(0, 0, 0); font-size: 16px; font-family: 'times new roman', 'new york', times, serif; background-color: transparent; font-style: normal;">If you want to do the math, t<span style="font-size: 12pt;">he simple way is to measure the current at full throttle, then plug the number into this equation:</span></div><div style="color: rgb(0, 0, 0); font-size: 12pt; font-family: 'times new roman', 'new york', times, serif;
background-color: transparent; font-style: normal;"><span style="background-color: transparent; font-size: 12pt;">Power = MaxCurrent * 1000 * Cell Resistance (in Milliohms) This will tell you how much power is being absorbed by the packs. More power absorbed is bad, less power absorbed is good.</span></div><div style="color: rgb(0, 0, 0); font-size: 12pt; font-family: 'times new roman', 'new york', times, serif; background-color: transparent; font-style: normal;"><span style="font-size: 12pt;"><br></span></div><div style="color: rgb(0, 0, 0); font-size: 16px; font-family: 'times new roman', 'new york', times, serif; background-color: transparent; font-style: normal;"><span style="font-size: 12pt;">Converting power absorbed into temperature rise over time is more complicated.</span></div><div style="color: rgb(0, 0, 0); font-size: 16px; font-family: 'times new roman', 'new york', times, serif; background-color: transparent; font-style:
normal;"><span style="font-size: 12pt;"> </span><br></div><div>Bob Kane<br>getterflash@yahoo.com</div><div><br></div> <div style="font-family: 'times new roman', 'new york', times, serif; font-size: 12pt;"> <div style="font-family: 'times new roman', 'new york', times, serif; font-size: 12pt;"> <div dir="ltr"> <hr size="1"> <font size="2" face="Arial"> <b><span style="font-weight:bold;">From:</span></b> J N Hiller <jnhiller@earthlink.net><br> <b><span style="font-weight: bold;">To:</span></b> NSRCA Mailing List <nsrca-discussion@lists.nsrca.org> <br> <b><span style="font-weight: bold;">Sent:</span></b> Friday, July 26, 2013 3:30 PM<br> <b><span style="font-weight: bold;">Subject:</span></b> [NSRCA-discussion] LIPO Question<br> </font> </div> <div class="y_msg_container"><br>HELP!<br><br>I'm trying to understand battery heat gained from internal cell resistance.<br>Total resistance of brand A = 13, Brand B = 28 (Twin 5S 5000 packs -
new -<br>unused).<br><br>Can someone point me to a formula?<br><br>Thanks<br>Jim Hiller<br><br>_______________________________________________<br>NSRCA-discussion mailing list<br><a ymailto="mailto:NSRCA-discussion@lists.nsrca.org" href="mailto:NSRCA-discussion@lists.nsrca.org">NSRCA-discussion@lists.nsrca.org</a><br><a href="http://lists.nsrca.org/mailman/listinfo/nsrca-discussion" target="_blank">http://lists.nsrca.org/mailman/listinfo/nsrca-discussion</a><br><br><br></div> </div> </div> </div></body></html>