[NSRCA-discussion] LIPO Question

[John Gayer]

Jim,
The watts generated is equal to the internal resistance squared times 
the internal resistance.
So if you take a maximum like 80 amps and an internal resistance of 
.0015 ohms per cell in a 10S battery,
you get     *80.0 * 80.0 * .0015 * 10 = 96 watts. After that it is 
dependent on your cooling system and use of the throttle.

Essentially a 100 watt light bulb which effectively converts electricity 
into heat with a small byproduct of light. That is 96 watts you do not 
have available to turn the prop.

You can see that if you have a cell where the IR is out of line by 2-10 
times the nominal in the battery, that is very easy to blow out that 
cell due to overheating.
John

On 7/26/2013 1:30 PM, J N Hiller wrote:
> HELP!
>
> I'm trying to understand battery heat gained from internal cell resistance.
> Total resistance of brand A = 13, Brand B = 28 (Twin 5S 5000 packs - new -
> unused).
>
> Can someone point me to a formula?
>
> Thanks
> Jim Hiller
>
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