[NSRCA-discussion] Clarifications on certain maneuvers in the P and F sequences

[Derek Koopowitz]

My flying may certainly be qualified as ugly but done right, these look
just fine... LOL

On Tue, Apr 24, 2012 at 10:38 AM, Doug Cronkhite <seefo at san.rr.com> wrote:

> In all of your descriptions, I think you're right but also think that'll
> make for some ugly flying
>
>
>
> Sent from my iPhone
>
> On Apr 24, 2012, at 10:32 AM, Derek Koopowitz <derekkoopowitz at gmail.com>
> wrote:
>
> > I've had several conversations with different people about maneuvers
> P-13.03 (Consecutive three 1/4 Rolls followed by consecutive three 1/4
> rolls in the opposite direction), F-13.05 (Roll combination with
> consecutive 1/4 roll, two snap rolls opposite, 1/4 roll), F-13.09 (45
> degree upline with consecutive four 1/8 rolls followed by 1 1/2 snap in
> opposite direction) and F-13.11 (Clown dance with 1/2 loop, inverted 2 1/2
> turn spin and two 1/4 rolls down).
> >
> > In P-13.03 - there is no pause between the end of the 1st three 1/4
> rolls and the start of the second set of 1/4 rolls - the reversal must be
> immediate.  I think a lot of people are thinking of this maneuver as a 3 of
> 4 point roll followed by a 3 of 4 point roll opposite and thus want to put
> an extended line between the two sets of 3 of 4 point rolls.  Since these
> are three 1/4 rolls, there is no requirement to extend the line after the
> 3rd 1/4 roll to make it "symmetrical" and thus the roll reversal should
> start immediately after the plane finishes the third 1/4 roll.
> >
> > F-13.05 - There is no pause after the 1st snap and the 2nd snap should
> happen immediately after the 1st one.
> >
> > F-13.09 - This is just like P-13.03 in that the 1 1/2 snap roll must
> happen immediately after the four 1/8 rolls.  There is no line between the
> end of the fourth 1/8 roll and the snap roll.
> >
> > F-13.11 - Since this maneuver contains 2 elements (the 1/2 loop and then
> the spin), the center of the maneuver should be exactly in the middle - in
> other words, the distance to the outermost radius of the 1/2 loop (from the
> middle) is the same as the distance to the start of the spin entry.  As an
> example, this would be identical to the placement of a double immelman on
> center - 1/2 the maneuver will be to the left of center and the other half
> of the maneuver will be to the right of center.
> >
> > Comments/questions?
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