Nose weight

[Earl Haury]

What about using the nose weights I see the younger set sporting at the 
mall - something's gotta be massively dense there!

Earl
----- Original Message ----- 
From: "Keith Hoard" <khoard at midsouth.rr.com>
To: <discussion at nsrca.org>
Sent: Tuesday, March 15, 2005 5:32 PM
Subject: RE: Nose weight


> You guys are all thinking "inside the box".
> .
> .
> Have you tried pumping helium into the tail of your airplane. . . .
>
>
>
> Keith L. Hoard
> Cordova, TN
> khoard at midsouth.rr.com
>
>
>
> -----Original Message-----
> From: discussion-request at nsrca.org [mailto:discussion-request at nsrca.org] 
> On
> Behalf Of Scott Smith
> Sent: Tuesday, March 15, 2005 5:13 PM
> To: discussion at nsrca.org
> Subject: RE: Nose weight
>
> To calc the CG shift:
>
> Define a datum, any point from which all measurements are taken.
>
> Measurements to the left of that point are negative, and to the right are
> positive.  (Use the tip of the spinner and all measurements will be
> positive.)
>
> So you know the weight (say 280 oz) and you know the CG as measured from 
> the
> tip of the spinner (say 25").  If you stick a 5 oz weight 6" to the right 
> of
> the datum (spinner tip), the CG will move .33" forward.  This is 
> calculated
> by using Weight * Arm = Moment where Arm is the distance from the datum:
>
>          W     A    M
> EWCG     280 * 25 = 7000
> Ballast    5 *  6 =   30
>
> Sum the Weights and Moments and solve for the new Arm:
> 7030 / 285 = 24.67
>
> So the CG went from 25" aft of the spinner tip to 24.67"
>
> If you pick the current CG as the datum, then it becomes:
>         W       A     M
> EWCG    280  *   0  =   0
> Ballast   5  * -19  = -95
>       ====          =====
> Total   285           -95
>
> A = -95 / 285 or -.33
>
> So again, the CG is moved .33" forward.
>
>
> -----Original Message-----
> From: discussion-request at nsrca.org
> [mailto:discussion-request at nsrca.org]On Behalf Of John Ferrell
> Sent: Tuesday, March 15, 2005 10:11 AM
> To: discussion at nsrca.org
> Subject: Re: Nose weight
>
>
> Make a mold from aluminum foil to go inside the fuselage around the nose
> ring.
> melt the required amount of lead in a can with a propane torch.
> Pour lead into mold
> Either glue or screw the weight in place.
>
> Channel locks work better than straight pliers to handle can.
> Lead may be trimmed with pocket knife.
> Silicon (bathtub caulk) is easy to use and remove, but has a 24 hour cure
> time.
>
> Has anyone put together the math to figure out how far from the cg how 
> much
> weight is needed to move the cg how much?
> Knowns:
>    current cg
>    current airplane weight
>    weight to be added
> Find distance from current CG...
> Or from a reference point?
>
> John Ferrell
> http://DixieNC.US
>
> ----- Original Message -----
> From: "Steve Wiggin" <swiggin682 at cox.net>
> To: <discussion at nsrca.org>
> Sent: Monday, March 14, 2005 6:26 PM
> Subject: Nose weight
>
>
>>I have to add about 2 1/2 oz of weight to the nose of my pattern plane for
>>static balance. Has anyone ever tried pouring molten lead into an aluminum
>>spinner to get the weight as far forward as possible? I would probably 
>>have
>>to epoxy the weight in place and balance the spinner/weight, and wonder if
>>this would cause undue stress on the engine bearings. Any ideas would be
>>appreciated.
>> Steve
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