Nose weight

Tue Mar 15 14:42:26 AKST 2005

Wayne,
I've done that, at least when I got to the plane the tail was in the air.

Ken
----- Original Message ----- 
From: "Wayne Galligan" <wgalligan at goodsonacura.com>
To: <discussion at nsrca.org>
Sent: Tuesday, March 15, 2005 6:38 PM
Subject: Re: Nose weight

> Keith.... they should be trying transcendental meditation and levitate the
> tail.
>
> WG
>
>
> ----- Original Message ----- 
> From: "Keith Hoard" <khoard at midsouth.rr.com>
> To: <discussion at nsrca.org>
> Sent: Tuesday, March 15, 2005 5:32 PM
> Subject: RE: Nose weight
>
>
>> You guys are all thinking "inside the box".
>> .
>> .
>> Have you tried pumping helium into the tail of your airplane. . . .
>>
>>
>>
>> Keith L. Hoard
>> Cordova, TN
>> khoard at midsouth.rr.com
>>
>>
>>
>> -----Original Message-----
>> From: discussion-request at nsrca.org [mailto:discussion-request at nsrca.org]
> On
>> Behalf Of Scott Smith
>> Sent: Tuesday, March 15, 2005 5:13 PM
>> To: discussion at nsrca.org
>> Subject: RE: Nose weight
>>
>> To calc the CG shift:
>>
>> Define a datum, any point from which all measurements are taken.
>>
>> Measurements to the left of that point are negative, and to the right are
>> positive.  (Use the tip of the spinner and all measurements will be
>> positive.)
>>
>> So you know the weight (say 280 oz) and you know the CG as measured from
> the
>> tip of the spinner (say 25").  If you stick a 5 oz weight 6" to the right
> of
>> the datum (spinner tip), the CG will move .33" forward.  This is
> calculated
>> by using Weight * Arm = Moment where Arm is the distance from the datum:
>>
>>           W     A    M
>> EWCG     280 * 25 = 7000
>> Ballast    5 *  6 =   30
>>
>> Sum the Weights and Moments and solve for the new Arm:
>> 7030 / 285 = 24.67
>>
>> So the CG went from 25" aft of the spinner tip to 24.67"
>>
>> If you pick the current CG as the datum, then it becomes:
>>          W       A     M
>> EWCG    280  *   0  =   0
>> Ballast   5  * -19  = -95
>>        ====          =====
>> Total   285           -95
>>
>> A = -95 / 285 or -.33
>>
>> So again, the CG is moved .33" forward.
>>
>>
>> -----Original Message-----
>> From: discussion-request at nsrca.org
>> [mailto:discussion-request at nsrca.org]On Behalf Of John Ferrell
>> Sent: Tuesday, March 15, 2005 10:11 AM
>> To: discussion at nsrca.org
>> Subject: Re: Nose weight
>>
>>
>> Make a mold from aluminum foil to go inside the fuselage around the nose
>> ring.
>> melt the required amount of lead in a can with a propane torch.
>> Pour lead into mold
>> Either glue or screw the weight in place.
>>
>> Channel locks work better than straight pliers to handle can.
>> Lead may be trimmed with pocket knife.
>> Silicon (bathtub caulk) is easy to use and remove, but has a 24 hour cure
>> time.
>>
>> Has anyone put together the math to figure out how far from the cg how
> much
>> weight is needed to move the cg how much?
>> Knowns:
>>     current cg
>>     current airplane weight
>>     weight to be added
>> Find distance from current CG...
>> Or from a reference point?
>>
>> John Ferrell
>> http://DixieNC.US
>>
>> ----- Original Message -----
>> From: "Steve Wiggin" <swiggin682 at cox.net>
>> To: <discussion at nsrca.org>
>> Sent: Monday, March 14, 2005 6:26 PM
>> Subject: Nose weight
>>
>>
>> >I have to add about 2 1/2 oz of weight to the nose of my pattern plane
> for
>> >static balance. Has anyone ever tried pouring molten lead into an
> aluminum
>> >spinner to get the weight as far forward as possible? I would probably
> have
>> >to epoxy the weight in place and balance the spinner/weight, and wonder
> if
>> >this would cause undue stress on the engine bearings. Any ideas would be
>> >appreciated.
>> > Steve
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>>
>>
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>
>
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