[NSRCA-discussion] Electrical Help

[Phil S.]

Larry, haven't been there in the winter months, but trudging across snow 
in Glacier Nat. Park in July was enough for me -- getting to a 
still-frozen lake...in JULY!!!

Phil Spelt, KCRC Emeritus, Past President
AMA 1294 Scientific Leader Member
SPA L-18, Board Member
(865)435-1476v, (865)604-0541c


On 10/23/2013 6:10 PM, Larry & Eileen Fitch wrote:
> Phil,
> So I see you have been there too.  I remember waiting for the bus at 
> 06:00 to ride to A1W and the temp was 40 below zero, and there was a 
> breeze as well.
> Larry
>
>     ----- Original Message -----
>     *From:* Phil S. <mailto:chuenkan at comcast.net>
>     *To:* General pattern discussion
>     <mailto:nsrca-discussion at lists.nsrca.org>
>     *Sent:* Wednesday, October 23, 2013 1:09 PM
>     *Subject:* Re: [NSRCA-discussion] Electrical Help
>
>     And November, and February, and March, and April, and...lol
>
>     Phil Spelt, KCRC Emeritus, Past President
>     AMA 1294 Scientific Leader Member
>     SPA L-18, Board Member
>     (865)435-1476v, (865)604-0541c
>
>
>     On 10/23/2013 3:19 PM, Larry & Eileen Fitch wrote:
>>     In Idaho Falls, Idaho, in December and January, you can push with
>>     a rope.
>>     Just say'n
>>     Larry Fitch
>>
>>         ----- Original Message -----
>>         *From:* Keith Hoard <mailto:klhoard at hotmail.com>
>>         *To:* General pattern discussion
>>         <mailto:nsrca-discussion at lists.nsrca.org>
>>         *Sent:* Wednesday, October 23, 2013 10:47 AM
>>         *Subject:* Re: [NSRCA-discussion] Electrical Help
>>
>>         And you can't push with a rope.
>>
>>         Sent from my iPhone
>>
>>         On Oct 23, 2013, at 12:16, "Patrick Harris"
>>         <harris7148 at gmail.com <mailto:harris7148 at gmail.com>> wrote:
>>
>>>         The formula for voltage drop is: Voltage Drop = I times R
>>>
>>>         I = current in Amps
>>>         R = Resistance of the conductor in Ohms
>>>
>>>         So for any given length of wire, the resistance will
>>>         increase as the size of the conductor deceases and the
>>>         voltage will drop for any given level of draw (amps).
>>>
>>>         In other words in your case, lets say you put a load on the
>>>         circuit of a given length that draws x amount of amps, you
>>>         will see a voltage drop as the conductor size reduces
>>>         (resistance increases).
>>>
>>>         As the formula is stated, if you have no "current" draw, you
>>>         will have no voltage drop, but why would you have a circuit
>>>         if you didn't put a load on it?  In other words the voltage
>>>         will drop.
>>>
>>>         This will calculate it for you.
>>>
>>>         http://www.calculator.net/voltage-drop-calculator.html
>>>
>>>
>>>         On Wed, Oct 23, 2013 at 3:42 AM, Del R
>>>         <drykert2 at rochester.rr.com
>>>         <mailto:drykert2 at rochester.rr.com>> wrote:
>>>
>>>             Ron .. I think you are referring to current or
>>>             amperage.. Voltage won't show a drop.. 14 gauge is a no
>>>             no.. except for lighting basically.. Low current drain.
>>>                 Del
>>>
>>>                 ----- Original Message -----
>>>                 *From:* Ron Hansen <mailto:rcpilot at wowway.com>
>>>                 *To:* NSCRA Discussion List
>>>                 <mailto:nsrca-discussion at lists.nsrca.org>
>>>                 *Sent:* Tuesday, October 22, 2013 10:35 PM
>>>                 *Subject:* [NSRCA-discussion] Electrical Help
>>>
>>>                 For a 120 VAC system, can anyone tell me what the
>>>                 voltage drop will be over a give length of 10 gauge,
>>>                 12 gauge and 14 gauge copper wiring?
>>>
>>>                 Thanks
>>>
>>>                 Ron
>>>
>>>
>>>
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