[NSRCA-discussion] Correct Geometry on N

[Stuart Chale]

Yes I see what you mean now.
Strange :)
Stuart

James Oddino wrote:
> "The figure is equally tall as it is wide."   No it isn't.  
> Horizontally it is as large as the diameter of the circle.  Vertically 
> it is the distance across the flats which is less.
>
> Jim O
>
>
> On Jul 8, 2008, at 2:01 PM, Stuart Chale wrote:
>
>> OK lets see if this works.
>> In the attached drawing there is a hexagon with sharp corners.  Drawn 
>> symmetrically.  Superimposed is the same 6 sided figure with radiused 
>> corners.   Around this one is a circle just touching each radius.  
>> The figure is equally tall as it is wide.
>>
>> Stuart
>>
>> atwoodm at paragon-inc.com wrote:
>>> I gotta go with Richard on this. The length of sides of a 30/60/90 
>>> triangle are X(short side), 2X (hypotenuse), X * square root of 3 
>>> (medium side).  If we make X = 1 then the height of the hexagon  
>>> will always be 3.46  but the width will very as the side "points" 
>>> are trimmed by the increasing radius.  With zero radius, the width 
>>> in my example would be 4 (thus richards 1.15 ratio).  As the radius 
>>> grows the width narrows.
>>> Does someone with Cad want to draw this up?
>>>
>>> Its somewhat irrelevant. If the angles are correct, and there's 
>>> symmetry, and equal line lengths, the actual shape will be correct 
>>> regardless of "roundness"
>>>
>>> Sent from my BlackBerry Smartphone provided by Alltel
>>>
>>>
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