[NSRCA-discussion] Correct Geometry on N

[James Oddino]

"The figure is equally tall as it is wide."   No it isn't.   
Horizontally it is as large as the diameter of the circle.  Vertically  
it is the distance across the flats which is less.

Jim O


On Jul 8, 2008, at 2:01 PM, Stuart Chale wrote:

> OK lets see if this works.
> In the attached drawing there is a hexagon with sharp corners.   
> Drawn symmetrically.  Superimposed is the same 6 sided figure with  
> radiused corners.   Around this one is a circle just touching each  
> radius.  The figure is equally tall as it is wide.
>
> Stuart
>
> atwoodm at paragon-inc.com wrote:
>> I gotta go with Richard on this. The length of sides of a 30/60/90  
>> triangle are X(short side), 2X (hypotenuse), X * square root of 3  
>> (medium side).  If we make X = 1 then the height of the hexagon   
>> will always be 3.46  but the width will very as the side "points"  
>> are trimmed by the increasing radius.  With zero radius, the width  
>> in my example would be 4 (thus richards 1.15 ratio).  As the radius  
>> grows the width narrows.
>> Does someone with Cad want to draw this up?
>>
>> Its somewhat irrelevant. If the angles are correct, and there's  
>> symmetry, and equal line lengths, the actual shape will be correct  
>> regardless of "roundness"
>>
>> Sent from my BlackBerry Smartphone provided by Alltel
>>
>>
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