[NSRCA-discussion] Lasers

[J.Oddino]

How about this:

F to C
Add 40
multiply by 5/9
subtract 40

C to F
Add 40
multiply by 9/5
subtract 40

Can you see why this is a better way to remember the equations?

About the time I got out of the engineering business, I believe we dropped the degrees.  In other words it is 32F not 32 degrees F.

Jim O
  ----- Original Message ----- 
  From: Ron Van Putte 
  To: NSRCA Mailing List
  Sent: Thursday, January 11, 2007 7:42 PM
  Subject: Re: [NSRCA-discussion] Lasers




  On Jan 11, 2007, at 9:30 PM, Fred Huber wrote:


    the actual conversion is F = (9/5)*C +32.  
    You can test the conversion factor easilly.  
    -40F = -40C and  212 F = 100 C. (simultaneous equation solving on those two is how the conversion formula is derived)


  Not to quibble (he quibbled) , the two conditions for which the equation was developed were the freezing point and boiling point of water.  0C = 32F and 100C = 212F.  -40F or C was a result of the equation, not a criteria in its development.


  Ron Van Putte

      ----- Original Message ----- 
      From: JonLowe at aol.com 
      To: nsrca-discussion at lists.nsrca.org 
      Sent: Thursday, January 11, 2007 9:10 PM
      Subject: Re: [NSRCA-discussion] Lasers


      In a message dated 1/11/2007 8:45:33 PM Central Standard Time, natpenton at centurytel.net writes:
        Tom
        We don't know what 38C is. Sounds cold. Happy NewYear.         Nat
      Easy way approximation:

      F=(Cx2) + 30

      F=(38x2) + 30

      F= 106 = Damn hot!

      Jon Lowe




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