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<DIV><FONT face=Arial size=2>How about this:</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2><STRONG>F to C</STRONG></FONT></DIV>
<DIV><FONT face=Arial size=2>Add 40</FONT></DIV>
<DIV><FONT face=Arial size=2>multiply by 5/9</FONT></DIV>
<DIV><FONT face=Arial size=2>subtract 40</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2><STRONG>C to F</STRONG></FONT></DIV>
<DIV><FONT face=Arial size=2>Add 40</FONT></DIV>
<DIV><FONT face=Arial size=2>multiply by 9/5</FONT></DIV>
<DIV><FONT face=Arial size=2>subtract 40</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Can you see why this is a better way to remember
the equations?</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>About the time I got out of the engineering
business, I believe we dropped the degrees. In other words it is 32F not
32 degrees F.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Jim O</FONT></DIV>
<BLOCKQUOTE
style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=vanputte@cox.net href="mailto:vanputte@cox.net">Ron Van Putte</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> NSRCA Mailing List</DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Thursday, January 11, 2007 7:42
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [NSRCA-discussion]
Lasers</DIV>
<DIV><BR></DIV><BR>
<DIV>
<DIV>On Jan 11, 2007, at 9:30 PM, Fred Huber wrote:</DIV><BR
class=Apple-interchange-newline>
<BLOCKQUOTE type="cite">
<DIV><FONT face="Times New Roman">the actual conversion is F = (9/5)*C
+32. </FONT></DIV>
<DIV><FONT face="Times New Roman">You can test the conversion factor
easilly. </FONT></DIV>
<DIV><FONT face="Times New Roman">-40F = -40C and 212 F = 100 C.
(simultaneous equation solving on those two is how the conversion formula is
derived)</FONT></DIV></BLOCKQUOTE>
<DIV><BR class=khtml-block-placeholder></DIV>Not to quibble (he quibbled) ,
the two conditions for which the equation was developed were the freezing
point and boiling point of water. 0C = 32F and 100C = 212F. -40F
or C was a result of the equation, not a criteria in its development.</DIV>
<DIV><BR class=khtml-block-placeholder></DIV>
<DIV>Ron Van Putte<BR>
<BLOCKQUOTE type="cite">
<BLOCKQUOTE
style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=JonLowe@aol.com href="mailto:JonLowe@aol.com">JonLowe@aol.com</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=nsrca-discussion@lists.nsrca.org
href="mailto:nsrca-discussion@lists.nsrca.org">nsrca-discussion@lists.nsrca.org</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Thursday, January 11, 2007 9:10
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [NSRCA-discussion]
Lasers</DIV>
<DIV><BR></DIV>
<DIV>
<DIV>
<DIV>In a message dated 1/11/2007 8:45:33 PM Central Standard Time, <A
href="mailto:natpenton@centurytel.net">natpenton@centurytel.net</A>
writes:</DIV>
<BLOCKQUOTE
style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: blue 2px solid"><FONT
face=Arial>Tom<BR>We don't know what 38C is. Sounds cold. Happy
NewYear. Nat</FONT></BLOCKQUOTE></DIV>
<DIV>Easy way approximation:</DIV>
<DIV> </DIV>
<DIV>F=(Cx2) + 30</DIV>
<DIV> </DIV>
<DIV>F=(38x2) + 30</DIV>
<DIV> </DIV>
<DIV>F= 106 = Damn hot!</DIV></DIV>
<DIV> </DIV>
<DIV><FONT size=2 ptsize="10">Jon Lowe<BR></FONT></DIV>
<DIV><BR class=khtml-block-placeholder></DIV>
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