PUZZLE!

[Atwood, Mark]

DING DING DING...we have a winner. Sort of...     The number is
right...meaning that you're taking the size of the sphere as the
diameter of the cylinder approaches zero.  

 

All your missing is the key assumption...that the volume of the
remaining material remains constant regardless of the size of the
Sphere...which is true.

 

Now...for the big bonus...do the proof!!!!   (FYI, the proof is a pain)

 

________________________________

From: discussion-request at nsrca.org [mailto:discussion-request at nsrca.org]
On Behalf Of Ken Thompson
Sent: Monday, August 15, 2005 4:01 PM
To: discussion at nsrca.org
Subject: Re: PUZZLE!

 

This is just a wild guess, I'm not real good at these.

 

If the hole is of a very small diameter that would make the sphere 6
inches in diameter.  

 

If the sphere is 6" in diameter than the resulting volume would be...4/3
x pi x r cubed  or  113.09733552924001

 

That's the best I can do on short notice, with my minimal remaining
brain cells.

 

Ken

	----- Original Message ----- 

	From: Atwood, Mark <mailto:atwoodm at paragon-inc.com>  

	To: discussion at nsrca.org 

	Sent: Monday, August 15, 2005 3:12 PM

	Subject: PUZZLE!

	 

	Ok...this is by no means Airplane related, but it seems to me
that with all the engineers that solicit this list-serve, we could have
some fun with a few puzzles...  So since it's slow (While we wait for
the worlds to start next week) I thought I'd post a fun one.

	 

	Imagine a Sphere that has a cylindrical hole bored through the
center, the diameter of which results in the remaining hole being 6
inches long.  What is the volume of the remaining material in the
sphere??

	 

	And yes, you have enough information, and yes, I'm looking for a
numerical, absolute answer!!

	 

	-Mark

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