Center of loop

[george kennie]

Initially I was ready to debate this one, as I saw the length of the 45
Degree up, to one side of the vertical up, as being equal in length to
the diameter of the loop on the opposite side of the vertical up and
therefore the vertical up should represent the center, but there are a
couple of other elements to consider. Remember, we are required to
execute an entry and exit line of equal length. The end of the exit line
would therefore be much closer to the vertical up than the beginning of
the entry line.If you take these two lines into account, as indeed we
must, you will then see that this shifts the center location toward the
45 up and indeed Mr. Kababjian is correct, in my opinion, that the
center of the 45 up should represent the center of the maneuver.
   Thanks Don for the stimulation.
Georgie

Rcmaster199 at aol.com wrote:

> In a message dated 3/20/2003 9:09:28 PM Eastern Standard Time,
> dszczur at maranatha.net writes:
>
>
>
>> Subj:Center of loop
>> Date:3/20/2003 9:09:28 PM Eastern Standard Time
>> From:dszczur at maranatha.net
>> Reply-to:discussion at nsrca.org
>> To:discussion at nsrca.org
>> Sent from the Internet
>>
>>
>>
>> Center maneuver, pull 45 degrees, 7/8 outside loop to verical, two
>> point
>> roll up, exit upright.
>>
>> Where is the center?  P03 Aresti sequence shows center is the loop
>> center,
>> IAC/full scale says center is the middle of the 45 degree line.  By
>> pattern
>> definition, the center of whole maneuver is  maybe the vertical up
>> line-
>> which is it?
>>
>> Thanks,
>> Don
>
> Don,
>
> There are several elements but only three parts, the 45 deg up line,
> the 7/8 loop, and the vert w/ 2 pt roll to upright. I believe the
> IAC/full scale is correct= the middle of the 45 deg up line.
>
> Matt Kebabjian
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