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<DIV><FONT face=Tahoma>I'll take a stab at answering all your
questions..</FONT></DIV>
<DIV><FONT face=Tahoma></FONT><BR>Questions:</DIV>
<DIV>Where does the maneuver start?</DIV>
<DIV><FONT face=Tahoma>*** As far as I am concerned, it better start when you
call 'entering the box'. This, of course is not 'official', but if your wings
are still finding level, and you are climbing and decending, it's not very good
presentation for the judges, and I would take off something for this. I think
officially it's something like 100' before you start to roll to KE... but one
never knows when the roll will start, so level flight all the way from box entry
is a good idea.</FONT></DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV> At a point in the upright level flight before the knife edge that is
equal to the length of the knife edge?</DIV>
<DIV><FONT face=Tahoma>*** Upright level flight is WAY MORE than the KE
segment - not sure what you are asking here. </FONT></DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV>Is that part of the level flight considered point 1? (NO) - but this
is an interesting point. If you actually plot out a 4-point roll, the last
'point' is level flight and it's equal to the length of the KE and inverted
segements. However, this is not counted as a point because the CENTER of the
4-point is the center of inverted flight - this is where the Center defination
comes in of N-1 where N is the number of points in a roll. So in a 4 point, the
center is 4-1 = 3 segments, and at 1.5 segments (the center of inverted flight)
is the center of the maneuver.</DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV>Is any level flight required before the full roll?</DIV>
<DIV>*** Of course, you are flying a square with rounded corners. There is level
flight across the top and on the bottom (before the 2 of 4) before these rolls.
I suppose in theory you could start an immediate slow roll after the 1/2 loop
and make the slow roll the length of the diameter of the 1/2 loop, and this may
be OK, but you will not see this.</DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV>Where does the maneuver end? </DIV>
<DIV>*** It ends 100' after the completion of the 'square'. IF we define the
start of the square, just when you cross the center line, the end is as you
cross the center line again + 100 feet. (give or take)</DIV>
<DIV><FONT face=Tahoma></FONT> </DIV>
<DIV>Is there still a requirement to have level entry and exits as there was
last time I read a rule book?</DIV>
<DIV>*** I think so.</DIV>
<DIV>sc</DIV>
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<DIV><FONT face=Tahoma></FONT><FONT face=Tahoma></FONT><BR></DIV>
<DIV>Just a little curious. Not enough to read a rule book.</DIV>
<DIV><FONT face=Tahoma></FONT><FONT face=Tahoma></FONT><BR></DIV>
<DIV>Jim O</DIV>
<DIV><FONT face=Tahoma></FONT><BR></DIV>
<DIV><BR>
<DIV>On May 2, 2008, at 7:44 AM, Derek Koopowitz wrote:<BR
class=Apple-interchange-newline>
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<P><FONT size=2><FONT face=Tahoma size=3>The official description from the
rule book is:<BR><BR>Reverse Split S and Split S Combo, 2/4-pt roll first,
full roll second, inverted exit.<BR><BR>From upright, perform 2 points of a
4-pt roll, and push immediately to a half outside loop. Perform a
full<BR>roll, followed immediately by a half outside loop, to exit
inverted.</FONT></FONT></P>
<DIV><FONT size=2><FONT face=Tahoma size=3>Judging notes:<BR>1. The
outside half loops must follow immediately after the 2/4-pt roll and
roll.</FONT></FONT></DIV>
<DIV><FONT size=2><FONT face=Tahoma size=3>2. The length of the upper
horizontal line (including roll) is equal to the diameter of the half
loops. The geometric shape is that of a Double
Immelmann.<BR><BR></FONT>-----Original Message-----<BR>From: <A
href="mailto:nsrca-dist7-bounces@lists.nsrca.org">nsrca-dist7-bounces@lists.nsrca.org</A>
[<A
href="mailto:nsrca-dist7-bounces@lists.nsrca.org">mailto:nsrca-dist7-bounces@lists.nsrca.org</A>]
On Behalf Of Budd Engineering<BR>Sent: Friday, May 02, 2008 6:58 AM<BR>To:
CA, AZ, HI, NV, UT<BR>Subject: Re: [NSRCA-dist7] Clarification on FAI
maneuver 1<BR><BR>Hi all,<BR><BR>I'm pretty sure the following isn't correct
(IIRC Jason and the Canucks corrected me on it at Phoenix), because the
maneuver isn't a Double Immelman. It's probably worth checking on
though.<BR><BR>"the lenght of the upper horizontal line (including roll) is
equal tothe diameter of the half loops.<BR>The geometric shape is that of of
a Double Immelmann."<BR><BR>Thx, Jerry<BR><BR>Budd Engineering<BR><A
href="mailto:jerry@buddengineering.com">jerry@buddengineering.com</A><BR><A
href="http://www.buddengineering.com">http://www.buddengineering.com</A><BR><BR><BR>On
May 1, 2008, at 4:49 PM, Robert Gillespie wrote:<BR><BR>> the lenght of
the upper horizontal line (including roll) is equal<BR>> tothe diameter
of the half loops.<BR>> The geometric shape is that of of a Double
Immelmann.<BR><BR>_______________________________________________<BR>NSRCA-dist7
mailing list<BR>NSRCA-dist7@lists.nsrca.org<BR><A
href="http://lists.nsrca.org/mailman/listinfo/nsrca-dist7">http://lists.nsrca.org/mailman/listinfo/nsrca-dist7</A></FONT>
</DIV></DIV>_______________________________________________<BR>NSRCA-dist7
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