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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Stu,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Thanks for your response. I am hoping some more people see the comments and reply too. It really helps to have more eyes looking at this stuff. It is getting cold down here
in D2 as well. Can’t believe the flying season was so bad for rain this year. <o:p>
</o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Braxton Dudley<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"><o:p> </o:p></span></p>
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<p class="MsoNormal"><b><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">From:</span></b><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"> Stuart Chale <schale1@outlook.com>
<br>
<b>Sent:</b> Wednesday, October 24, 2018 9:58 AM<br>
<b>To:</b> Braxton Dudley <dudleyb1@outlook.com>; General pattern discussion <nsrca-discussion@lists.nsrca.org><br>
<b>Subject:</b> Re: [NSRCA-discussion] New K Factors<o:p></o:p></span></p>
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<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Braxton thank you for the explanation. I will have to look at some of the maneuvers to see how that is implemented.
<span style="font-size:11.0pt"><o:p></o:p></span></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt">I was hoping that I would start a more active conversation on the list but I guess everyone is either happy with the new system or already in hibernation for the winter. We seem to have bypassed the nice fall
weather and went right to the windy cold weather just north of you <span style="font-family:"Segoe UI Emoji",sans-serif">
🙂</span><o:p></o:p></p>
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<p class="MsoNormal">Sent from my iPhone<o:p></o:p></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt"><br>
On Oct 23, 2018, at 1:34 PM, Braxton Dudley via NSRCA-discussion <<a href="mailto:nsrca-discussion@lists.nsrca.org">nsrca-discussion@lists.nsrca.org</a>> wrote:<o:p></o:p></p>
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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Stu,</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">We really appreciate your comments. The Double Immelmann has only horizontal components(rolling components) so we do not divide the additional components by two as we do in
for example stall turns, and square loops with components on vertical, or vertical and horizontal legs. The vertical component must be there. That being said there is an inconsistency in the way the Double Immelmann with knife edge was calculated. We should
not have added in the ¼ rolls since the ¼ roll is assumed in the knife edge. Anything other than a ¼ roll will have additional kfactors added in for knife edge maneuvers. This and other comments will all be taken into account before actual implementation.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"> </span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">This is how the double Immelmann should be calculated.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Basic 2</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">KE 2</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">KE 2</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Total 6</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"> </span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Below is the wording for when we divide by two on additional components. The short explanation is if a maneuver only has horizontal rolling components there will be no dividing
by two.</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"> </span><o:p></o:p></p>
<p class="MsoNormal"><span style="color:#1F497D">“Any maneuver with multiple rolling elements and either, horizontal
<b>and</b> vertical components, <b>or</b> multiple vertical components, to the Kfactor for the base maneuver, add the Kfactor for the rolling element with the highest Kfactor as the initial added Kfactor, then on remaining rolling elements divide those Kfactors
by 2, and add them to the total . Examples of maneuvers: Square Loops, Double Stall Turns, etc.”</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;color:#1F497D"> </span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">Braxton Dudley</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">NSRCA Sequence Committee</span><o:p></o:p></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif"> </span><o:p></o:p></p>
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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri",sans-serif">_______________________________________________<br>
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