<html><head></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; ">Obviously you speak from experience.<div><br></div><div>Ron</div><div><br><div><div>On Oct 23, 2013, at 12:47 PM, Keith Hoard wrote:</div><br class="Apple-interchange-newline"><blockquote type="cite"><meta http-equiv="content-type" content="text/html; charset=utf-8"><div dir="auto"><div>And you can't push with a rope. <br><br>Sent from my iPhone</div><div><br>On Oct 23, 2013, at 12:16, "Patrick Harris" <<a href="mailto:harris7148@gmail.com">harris7148@gmail.com</a>> wrote:<br><br></div><blockquote type="cite"><div><div dir="ltr">The formula for voltage drop is: Voltage Drop = I times R<div><br></div><div>I = current in Amps</div><div>R = Resistance of the conductor in Ohms</div><div><br></div><div>So for any given length of wire, the resistance will increase as the size of the conductor deceases and the voltage will drop for any given level of draw (amps). </div>
<div><br></div><div>In other words in your case, lets say you put a load on the circuit of a given length that draws x amount of amps, you will see a voltage drop as the conductor size reduces (resistance increases). </div>
<div><br></div><div>As the formula is stated, if you have no "current" draw, you will have no voltage drop, but why would you have a circuit if you didn't put a load on it? In other words the voltage will drop.</div>
<div><br></div><div>This will calculate it for you.</div><div><br></div><div><a href="http://www.calculator.net/voltage-drop-calculator.html">http://www.calculator.net/voltage-drop-calculator.html</a><br></div></div><div class="gmail_extra">
<br><br><div class="gmail_quote">On Wed, Oct 23, 2013 at 3:42 AM, Del R <span dir="ltr"><<a href="mailto:drykert2@rochester.rr.com" target="_blank">drykert2@rochester.rr.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<u></u>
<div lang="EN-US" link="blue" bgcolor="#ffffff" vlink="purple">
<div><font color="#0000ff" face="Arial">Ron .. I think you are referring to
current or amperage.. Voltage won't show a drop.. 14 gauge is a no no.. except
for lighting basically.. Low current drain. </font></div>
<div><font color="#0000ff" face="Arial"> </font></div>
<div><font color="#0000ff" face="Arial"> Del</font></div>
<blockquote style="BORDER-LEFT:#0000ff 2px solid;PADDING-LEFT:5px;PADDING-RIGHT:0px;MARGIN-LEFT:5px;MARGIN-RIGHT:0px">
<div style="FONT:10pt arial">----- Original Message ----- </div>
<div style="FONT:10pt arial;BACKGROUND:#e4e4e4"><b>From:</b>
<a title="rcpilot@wowway.com" href="mailto:rcpilot@wowway.com" target="_blank">Ron Hansen</a>
</div>
<div style="FONT:10pt arial"><b>To:</b> <a title="nsrca-discussion@lists.nsrca.org" href="mailto:nsrca-discussion@lists.nsrca.org" target="_blank">NSCRA Discussion List</a>
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<div style="FONT:10pt arial"><b>Sent:</b> Tuesday, October 22, 2013 10:35
PM</div>
<div style="FONT:10pt arial"><b>Subject:</b> [NSRCA-discussion] Electrical
Help</div>
<div><br></div>
<div><p class="MsoNormal">For a 120 VAC system, can anyone tell me what the voltage
drop will be over a give length of 10 gauge, 12 gauge and 14 gauge copper
wiring?<u></u><u></u></p><p class="MsoNormal"><u></u> <u></u></p><p class="MsoNormal">Thanks<u></u><u></u></p><p class="MsoNormal"><u></u> <u></u></p><p class="MsoNormal">Ron<u></u><u></u></p></div><br><br>__________ Information from
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