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<p class=MsoNormal>A full scale friend lent me a book by Alan Cassidy entitled “Better
Aerobatics” which had a formula for determining how many Gs to pull to
enter a snap. It is very enlightening.<o:p></o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal>Formula is = Recommended entry speed to enter
snap divided by the Power ON stall speed - Squared.<o:p></o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal>His example (Pits S2A) was 105/55 =1.909
(1.909)2 =3.64 Gs. This means you would try to have an instantaneous
3.64 G loading if entering the “flick roll” at 105 mph. <o:p></o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal>What I find fascinating about the formula is the “power
on stall” part of the formula. Now translate that into our
models which have NO power ON stall speed. I think this means that mathematically
we cannot do a snap. Or the instantaneous Gs required are
impossible to obtain. <o:p></o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal><o:p> </o:p></p>
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