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<DIV><FONT size=2 face=Arial>Correct, otherwise the maneuver would need to be
called a 1/2 rectangle.</FONT></DIV>
<BLOCKQUOTE
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><B>From:</B>
<A title=vicenterc@comcast.net href="mailto:vicenterc@comcast.net">Vicente
"Vince" Bortone</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=nsrca-discussion@lists.nsrca.org
href="mailto:nsrca-discussion@lists.nsrca.org">General pattern discussion</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Sunday, September 27, 2009 8:30
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [NSRCA-discussion]
Interesting Masters schedule Judging Question</DIV>
<DIV><BR></DIV>
<DIV style="FONT-FAMILY: Arial; COLOR: #000000; FONT-SIZE: 12pt">
<P>Hi Joe,</P>
<P> </P>
<P>Here is my guess. It is very good question:</P>
<P> </P>
<P>The name of the maneuver takes precedence. We can adjust the altitude
by increasing or decreasing the length of both sides of the 1/2 square.
Therefore, both have to be equal. This is because we will need to
preserve the square shape. This is not necessarily the case in
other other turnaround maneuvers. </P>
<P> </P>
<P>I found the description. Here is:</P>
<P> </P><B><FONT size=2>
<P>Square Loop on Corner with Two Half Rolls: </B></FONT><FONT size=2
face="Times New Roman,Times New Roman">Model pulls through one-eighth (1/8)
loop to a 45- degree climb and completes a square loop. Model executes a half
roll in the first and third legs. Downgrades: </P></FONT><B><FONT size=2>
<P>1. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">All sides
not at 45 degrees to horizon. </P></FONT><FONT size=2>
<P><STRONG><EM>2. </EM></STRONG></FONT><FONT size=2
face="Times New Roman,Times New Roman"><STRONG><EM>Loop not square with sides
of equal length. </EM></STRONG></P></FONT><FONT size=2>
<P><STRONG>3. </STRONG></FONT><FONT size=2
face="Times New Roman,Times New Roman">Loop segments not round and of equal
radius. </P></FONT><B><FONT size=2>
<P>4. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Half
rolls not 180 degrees. </P></FONT><B><FONT size=2>
<P>5. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Wings not
level during one-quarter loops. </P></FONT><B><FONT size=2>
<P>6. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Changes
in heading during rolls and loops. </P></FONT><B><FONT size=2>
<P>7. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Rolls not
centered in legs. </P></FONT><B><FONT size=2>
<P>8. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Rolls not
in first and third legs score zero (0). </P></FONT><B><FONT size=2>
<P>9. </B></FONT><FONT size=2 face="Times New Roman,Times New Roman">Roll
rates not constant </P></FONT>
<P> </P>
<P>OK. I hope that this is clear. Have a
nice week. </P>
<P> </P>
<P><BR>Vicente "Vince" Bortone<BR><BR>----- Original Message -----<BR>From:
"Joe Dunnaway" <dunnaway@hbcomm.net><BR>To: "General pattern discussion"
<nsrca-discussion@lists.nsrca.org><BR>Sent: Sunday, September 27, 2009
8:05:43 PM GMT -06:00 US/Canada Central<BR>Subject: [NSRCA-discussion]
Interesting Masters schedule Judging Question<BR><BR> Can
the "Half Square on Corners /w half rolls" vary in length on the <BR>legs as
long as the rolls are centered in the lines? It is a turn <BR>around
maneuver and most turn around maneuvers can be used to adjust <BR>height.
<BR>My view would be that both legs should be equal but I can see where it
<BR>could be argued that since you are adjusting your exit height, you
<BR>should be able to vary the length.<BR><BR>Jeff Buchner asked me this at
the Ft. Scott contest and I'm not sure of <BR>the answer.<BR><BR><BR>Joe
D.<BR><BR><BR>_______________________________________________<BR>NSRCA-discussion
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list<BR>NSRCA-discussion@lists.nsrca.org<BR>http://lists.nsrca.org/mailman/listinfo/nsrca-discussion<BR></P></DIV>
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