<html><head><style type="text/css"><!-- DIV {margin:0px;} --></style></head><body><div style="font-family:times new roman,new york,times,serif;font-size:12pt">Well, from trig, the length of half the box at 150 meters is 150/(tan30) or 150/.577350 = 259.8072, which is dang close to 260 meters. Double that and the distance between the box end poles is 520 meters<br><div> </div>Bob Kane<br>getterflash@yahoo.com<div><br></div><div style="font-family: times new roman,new york,times,serif; font-size: 12pt;"><br><div style="font-family: times new roman,new york,times,serif; font-size: 12pt;"><font size="2" face="Tahoma"><hr size="1"><b><span style="font-weight: bold;">From:</span></b> ksutherland <ksutherland@hughes.net><br><b><span style="font-weight: bold;">To:</span></b> NSRCA-discussion@lists.nsrca.org<br><b><span style="font-weight: bold;">Sent:</span></b> Monday, May 11, 2009 10:17:52 PM<br><b><span style="font-weight:
bold;">Subject:</span></b> [NSRCA-discussion] How wide is the box<br></font><br>
Could someone tell me about how wide the box is pole to pole at 150 m ?<br>Thanks
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