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<DIV>If the lines are 45's there is no other answer is a square shape no matter
how long or short the 45's are all sides will be equal. that makes a
square.</DIV>
<DIV> </DIV>
<DIV><FONT face=Arial size=2>Ken</FONT></DIV>
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=bob@toprudder.com href="mailto:bob@toprudder.com">Bob Richards</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
title=nsrca-discussion@lists.nsrca.org
href="mailto:nsrca-discussion@lists.nsrca.org">General pattern discussion</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Tuesday, July 08, 2008 11:23
AM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [NSRCA-discussion] Correct
Geometry on N</DIV>
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<P>Unless my geometry is wrong (and I was really good at geometry in
schooll) then the only way it can be a square is if the corner radii are
= 0. It should always be a little wider than it is tall. If not,
then the diagonals are not 45 degree lines.</P>
<P> </P>
<P>Draw it on paper, or with CAD, and you will see.<BR><BR>Bob
R<BR><BR>--- On <B>Tue, 7/8/08, Chad Northeast <I><<A
href="mailto:chadnortheast@shaw.ca">chadnortheast@shaw.ca</A>></I></B>
wrote:<BR></P>
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<DIV id=yiv434356784>Its definitely a square,<BR><BR>Basically you
have two 45x45 right triangles with the right angle vertex's (the
90's) intersecting.<BR><BR>In that case the vertical lines are twice
the length of each triangles horizontal length (when oriented as an
hourglass), therefore two of them equal the height of the
verticals....and a square you have!<BR><BR>The 45 lines end up being
about 1.4 times longer than the vertical lines, if you fly the correct
geometry.<BR><BR>Chad<BR></DIV></BLOCKQUOTE></TD></TR></TBODY></TABLE>
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