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<TITLE>Re: [NSRCA-discussion] Correct Geometry on N</TITLE>
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<FONT FACE="Calibri, Verdana, Helvetica, Arial"><SPAN STYLE='font-size:11pt'>Hmmmm... I hate to say it, but I think your geometry is wrong :(.<BR>
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The size of the radii won’t matter (provided they’re all the same and smaller than the overall shape)...it has to be square to get 45deg lines. You’re simply taking a square and bisecting it with crossing lines that are at 45degree angles. Expanding the radii from 0 simply makes each straight segment smaller, it doesn’t change the drawing at all.<BR>
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I can draw the hourglass box and overlay a bunch of different radii over it without changing the overall shape.<BR>
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-M<BR>
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On 7/8/08 11:23 AM, "Bob Richards" <<a href="bob@toprudder.com">bob@toprudder.com</a>> wrote:<BR>
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</SPAN></FONT><BLOCKQUOTE><FONT FACE="Calibri, Verdana, Helvetica, Arial"><SPAN STYLE='font-size:11pt'>Unless my geometry is wrong (and I was really good at geometry in schooll) then the only way it can be a square is if the corner radii are = 0. It should always be a little wider than it is tall. If not, then the diagonals are not 45 degree lines. Draw it on paper, or with CAD, and you will see.<BR>
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Bob R<BR>
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--- On <B>Tue, 7/8/08, Chad Northeast <I><<a href="chadnortheast@shaw.ca">chadnortheast@shaw.ca</a>></I></B> wrote:<BR>
</SPAN></FONT><BLOCKQUOTE><FONT FACE="Calibri, Verdana, Helvetica, Arial"><SPAN STYLE='font-size:11pt'>Its definitely a square,<BR>
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Basically you have two 45x45 right triangles with the right angle vertex's (the 90's) intersecting.<BR>
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In that case the vertical lines are twice the length of each triangles horizontal length (when oriented as an hourglass), therefore two of them equal the height of the verticals....and a square you have!<BR>
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The 45 lines end up being about 1.4 times longer than the vertical lines, if you fly the correct geometry.<BR>
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Chad<BR>
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