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<DIV><FONT face=Arial size=2>In light of the clarification supplied by Richard
Lindburgh and the fact that we do not have a specific descriptor for the current
maneuver ( at least not that I have been able to find) I decided to try to
write one for myself. Here it is as I see it, and feel free to make the
necessary corrections, additions, deletions, e.t.c. where I am
wrong.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>HORIZONTAL SQUARE EIGHT.</FONT></DIV>
<DIV><FONT face=Arial size=2> </FONT></DIV>
<DIV><FONT face=Arial size=2>Model flies past center a distance equal to the
anticipated size of the first loop minus the length of the radius of the first
1/4 loop element at which point it pushes to a vertical upline and performs
three legs of an outside square loop with the third descending leg occurring on
the center line, the bottom of which line the model pulls to upright level
flight and performs an inside square loop the opposite side of center of equal
proportion to the first outside loop and at the completion of which the model
pushes to recover in inverted level flight.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>That's about as good as I'm going to be able to
come up with.</FONT></DIV></BODY></HTML>