[NSRCA-discussion] SNAPS ! AGAIN !
Bill Glaze
billglaze at bellsouth.net
Sun Feb 28 09:11:36 AKST 2010
John: Not a criticism; just wanted to make sure that you had seen the well-done essay. It is so good, that I saved it and made a hard copy for my "technical" file to boot; just making sure that I for-sure had it. Actually, I do that with a lot of the well-informed folks on this list.
Bill Glaze
----- Original Message -----
From: John Fuqua
To: 'General pattern discussion'
Sent: Sunday, February 28, 2010 12:42 PM
Subject: Re: [NSRCA-discussion] SNAPS ! AGAIN !
I read it. But this was new data about full scale (to me anyway), which we have been trying to mimic per the rule book forever, which brought clarity to me. Just thought I would share.
From: nsrca-discussion-bounces at lists.nsrca.org [mailto:nsrca-discussion-bounces at lists.nsrca.org] On Behalf Of Bill Glaze
Sent: Sunday, February 28, 2010 10:37 AM
To: General pattern discussion
Subject: Re: [NSRCA-discussion] SNAPS ! AGAIN !
Did you not read the essay by Jerry Budd a few months ago? Verified by Ron van Putte. Both are qualified aerodynamicists. I have done hours of studies on snap rolls and anallyzed them in slow motion, and they in no way fulfill the qualifications presently in the rule books.
The rules need rewording.
Bill Glaze
----- Original Message -----
From: Keith Hoard
To: General pattern discussion
Sent: Saturday, February 27, 2010 11:22 AM
Subject: Re: [NSRCA-discussion] SNAPS ! AGAIN !
Why would you let something as trivial as mathematics (or physics) get in your way?
On Sat, Feb 27, 2010 at 8:21 PM, Ron Van Putte <vanputte at cox.net> wrote:
Oh my! I hope John realizes what he's stepped in here.
Ron
On Feb 27, 2010, at 9:36 AM, John Fuqua wrote:
A full scale friend lent me a book by Alan Cassidy entitled “Better Aerobatics” which had a formula for determining how many Gs to pull to enter a snap. It is very enlightening.
Formula is = Recommended entry speed to enter snap divided by the Power ON stall speed - Squared.
His example (Pits S2A) was 105/55 =1.909 (1.909)2 =3.64 Gs. This means you would try to have an instantaneous 3.64 G loading if entering the “flick roll” at 105 mph.
What I find fascinating about the formula is the “power on stall” part of the formula. Now translate that into our models which have NO power ON stall speed. I think this means that mathematically we cannot do a snap. Or the instantaneous Gs required are impossible to obtain.
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Keith Hoard
Collierville, TN
khoard at gmail.com
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