[NSRCA-discussion] *SPAM* Re: How wide is the box

[Atwood, Mark]

That should be right. Simple 30/60/90 triangle. X / 2X / X radical 3


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----- Original Message -----
From: nsrca-discussion-bounces at lists.nsrca.org <nsrca-discussion-bounces at lists.nsrca.org>
To: General pattern discussion <nsrca-discussion at lists.nsrca.org>
Sent: Mon May 11 22:24:42 2009
Subject: *SPAM* Re: [NSRCA-discussion] How wide is the box

Mark, I believe your right.

Matt
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----- Original Message ----- 
From: "Atwood, Mark" <atwoodm at paragon-inc.com>
To: <nsrca-discussion at lists.nsrca.org>
Sent: Monday, May 11, 2009 9:20 PM
Subject: Re: [NSRCA-discussion] How wide is the box


> 300meters x square root of 3
>
> Or 519.6 meters
>
> I think :)
> --------------------------
> Sent from my BlackBerry Wireless Handheld
>
>
> ----- Original Message -----
> From: nsrca-discussion-bounces at lists.nsrca.org 
> <nsrca-discussion-bounces at lists.nsrca.org>
> To: NSRCA-discussion at lists.nsrca.org <NSRCA-discussion at lists.nsrca.org>
> Sent: Mon May 11 22:17:52 2009
> Subject: [NSRCA-discussion] How wide is the box
>
> Could someone tell me about how wide the box is pole to pole at 150 m ?
> Thanks
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> NSRCA-discussion at lists.nsrca.org
> http://lists.nsrca.org/mailman/listinfo/nsrca-discussion
>


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