[NSRCA-discussion] Correct Geometry on N
Stuart Chale
schale at optonline.net
Tue Jul 8 13:01:58 AKDT 2008
OK lets see if this works.
In the attached drawing there is a hexagon with sharp corners. Drawn
symmetrically. Superimposed is the same 6 sided figure with radiused
corners. Around this one is a circle just touching each radius. The
figure is equally tall as it is wide.
Stuart
atwoodm at paragon-inc.com wrote:
> I gotta go with Richard on this. The length of sides of a 30/60/90 triangle are X(short side), 2X (hypotenuse), X * square root of 3 (medium side). If we make X = 1 then the height of the hexagon will always be 3.46 but the width will very as the side "points" are trimmed by the increasing radius. With zero radius, the width in my example would be 4 (thus richards 1.15 ratio). As the radius grows the width narrows.
>
> Does someone with Cad want to draw this up?
>
> Its somewhat irrelevant. If the angles are correct, and there's symmetry, and equal line lengths, the actual shape will be correct regardless of "roundness"
>
>
> Sent from my BlackBerry Smartphone provided by Alltel
>
>
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