[NSRCA-discussion] Chapter-12 computer science.

[Matthew Frederick]

Oh yeah... and I can't remember ever programming in 8-bits...

----- Original Message ----- 
From: "Duane Beck" <duane.e.beck at comcast.net>
To: "NSRCA Mailing List" <nsrca-discussion at lists.nsrca.org>
Sent: Wednesday, July 04, 2007 12:16 AM
Subject: Re: [NSRCA-discussion] Chapter-12 computer science.


> Depends on whether char basic type is 8-bit or larger.  Most decent 
> compilers should issue a warning for comparing with an integer constant 
> out of range.  Assuming default char type is 8-bit signed, when cnt is 
> 127, cnt increments to -128 (by wrapping around adjacent two's 
> complement values) and the loop continues unterminated.  If default char 
> type is 8-bit unsigned, it's still unterminated because after 255, cnt 
> will increment to 0.  So, in both conditions, cnt is always less than 
> 256.  Otherwise, if char is larger (16-bit), foo returns 256.
> 
> Duane
> 
> Martin X. Moleski, SJ wrote:
>> John Pavlick wrote:
>>> OK, what does this do?
>> 
>>> char foo(void)
>>> {
>>>      char cnt, num;
>>>
>>>     for(cnt = 0, num = 0; cnt < 256; cnt++)
>>>     {
>>>          num++;
>>>     }
>>>     return num;
>>> }
>> 
>> 
>> Initializes cnt and num to 0.
>> 
>> Increments cnt and num from 0 to 255
>> by passing through the for loop.
>> 
>> Returns 255.
>> 
>> 
>> Marty
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>> 
> 
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