[NSRCA-discussion] Chapter-12 computer science.

[Ryan Smith]

Sooo...

Am I the only one that feels like a dunce? I think when I start classes
back, I'm going to take some more computer science classes.

Ryan

-----Original Message-----
From: nsrca-discussion-bounces at lists.nsrca.org
[mailto:nsrca-discussion-bounces at lists.nsrca.org] On Behalf Of Duane Beck
Sent: Wednesday, July 04, 2007 1:17 AM
To: NSRCA Mailing List
Subject: Re: [NSRCA-discussion] Chapter-12 computer science.

Depends on whether char basic type is 8-bit or larger.  Most decent 
compilers should issue a warning for comparing with an integer constant 
out of range.  Assuming default char type is 8-bit signed, when cnt is 
127, cnt increments to -128 (by wrapping around adjacent two's 
complement values) and the loop continues unterminated.  If default char 
type is 8-bit unsigned, it's still unterminated because after 255, cnt 
will increment to 0.  So, in both conditions, cnt is always less than 
256.  Otherwise, if char is larger (16-bit), foo returns 256.

Duane

Martin X. Moleski, SJ wrote:
> John Pavlick wrote:
>> OK, what does this do?
> 
>> char foo(void)
>> {
>>      char cnt, num;
>>
>>     for(cnt = 0, num = 0; cnt < 256; cnt++)
>>     {
>>          num++;
>>     }
>>     return num;
>> }
> 
> 
> Initializes cnt and num to 0.
> 
> Increments cnt and num from 0 to 255
> by passing through the for loop.
> 
> Returns 255.
> 
> 
> 			Marty
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> 

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