[NSRCA-discussion] Thrust line calculation

[vicenterc at comcast.net]

or tan-1 of .625"/16" = 2.24 degrees.  

Vicente "Vince" Bortone



-------------- Original message -------------- 
From: "Scott Smith" <js.smith at verizon.net> 

> Assuming a 16" prop, 2.24 degrees. 
> 
> Just plug your numbers in here: 
> http://www.carbidedepot.com/formulas-trigright.asp 
> 
> side A: .625 
> side B: 16 
> Click calculate 
> Angle A is your answer 
> 
> -----Original Message----- 
> From: nsrca-discussion-bounces at lists.nsrca.org 
> [mailto:nsrca-discussion-bounces at lists.nsrca.org] On Behalf Of 
> adriancwong at earthlink.net 
> Sent: Monday, February 19, 2007 5:13 AM 
> To: NSRCA Mailing List 
> Subject: Re: [NSRCA-discussion] Thrust line calculation 
> 
> To all, 
> 
> Does anyone know how to translate from inches to degrees in thrust line 
> calculation. 
> 
> For example, from the stab to the left tip of the prop is 58-11/16", and the 
> other side is 58-1/16". Therefore, the difference is 5/8 ", what would be my 
> degree of right thrust? 
> 
> Thanks in advance, 
> 
> Adrian 
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