[NSRCA-discussion] Square Eight

Tue Nov 14 10:52:55 AKST 2006

Comment. I assume that the square horizontal eight is a derivative of the Cuban eight.  If that is the case, the aircraft has to pass the center when starting the maneuver so only one option is possible.  I checked the versions of eights in the AMA rule book and that is the only description I can find.  If the maneuver were called reverse square horizontal eight the second option would  be valid.

Am I correct?

Vicente "Vince" Bortone

-------------- Original message -------------- 
From: "george w. kennie" <geobet at gis.net> 

Hey Jim,
My hat's off to you for figuring this one out in the way that's supported by the rulebook. The way that Jerry likes it performed is how Vicente and I originally envisioned it and is actually the most logical to me, but the rulebook supports your original execution procedure. Yup, it can be done more than one way, but the book doesn't grant us an option. Both ways it's a centered maneuver, but the start point is not at center when performed according to the book.
I think you scooped us on this one Jim. Way to go.
G.

----- Original Message ----- 
From: jivey61 at bellsouth.net 
To: NSRCA Mailing List 
Sent: Tuesday, November 14, 2006 12:39 PM
Subject: Re: [NSRCA-discussion] Square Eight

Jerry 
So now there is 2 ways to do the 8?
......and you want the 1st vertical segment to be on center.That will work too.....
Look people I have flown this Horizontal 8 every way it can be flown in controlline stunt many years ago......Just tell me which way to fly this one,now.

Jim Ivey
----- Original Message ----- 
From: Jerry Stebbins 
To: Discussion -NSRCA 
Sent: Tuesday, November 14, 2006 11:56 AM
Subject: [NSRCA-discussion] Square Eight

Mr. Ivey, sir, maybe this will help.(and others also) 
We all know there are eight (8) lines and (8) corners to the maneuver.
We all know it is centered- so one half is on each side of center.
We all know one half of the maneuver is an outside square, and the other is an inside square.
One would assume that if you have to enter it inverted the first half would be the "outside half"
Also since you enter inverted and "low" -then one would assume that the maneuver is above that entry line.
I assume there are really entry and exit lines before and after the maneuver, so where the maneuver "starts" is what we are striving for.
Most of us (writer not included) can tell where center is--
soooo---there are two versions on how to do this flying around so lets sort that out also--One version performs the first "outside corner" (push) after center as the first maneuver, the other starts the maneuver on center with the first "outside corner" (push). Maybe there is a clue there since this is a "centered" maneuver.
First Version
If you enter the maneuver with a straight line -low - then the first line past center is either the beginning of the maneuver, or not a part of the maneuver, since you have gone past the last corner (on center), and did not do it. Some have said you will never be back to the center in the exactly same attitude again (not totally true since you do enter and exit inverted) during the maneuver so maybe that helps us narrow it down.
Also if the first three corners are "pushes" and the next four are "pulls" that leaves one "push" left to do.
OK everyone following so far--we have a "push" corner left to go, for sure,and a horizontal inverted line to define as either the "beginning" or the "end" of the maneuver.
You could say that you started the maneuver when you went past center, but that would not be "technically correct" since you have to couple the last corner to the line, and it would be a right angle-no length radius to be correct, plus that would force you into an automatic downgrade since it would not be like the other seven--never could do a perfect 10.
So now do we split the first line into a "start point" that is "some" distance after center so the "end point" of the "corner" has a defineable location, OR find an answer that allows a "10" and is "judgeable" 
So I would suggest the following would clarify this one. 1) the first part of the maneuver that is judged is the start of the first radius (lets not argue the entrance and exit line existence), and the last part that is judged is the straight line after the eight (8) radius "push" that is of proper length for the "square" geometry, at the same altitude and same track to intersect the "start" point of the first "push" .
This is doable but does not seem like a reasonable way to end  up a "centered" maneuver
Version Two
Again lets not flog the (entrance and exit lines-they exist)
The maneuver starts inverted and low  with the first part that is judged is the first corner "push" to vertical "on center" to start the "inside" square, followed by four equal lines and "pulls" (last one on center to vertical), followed by three (3) more lines and "pushes" and then the eight (8) and last line judged is the straight line of proper length for the "square" geometry, at the same altitude and same track as the entrance line at the start of the first corner (push), that started the maneuver on "center".
This makes more sense as it actually "does something" on center to start a "centered" maneuver. Also this matches the Aresti diagram--for what that is worth in the AMA world.
I think what is confusing some is the fact that not all "pushes" and "pulls' follow each other.
I vote for this one! --And no need for a flame suit since all I will have to do is Judge it, not Fly it.
Jerry

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From: "george w. kennie" <geobet at gis.net>
Subject: Re: [NSRCA-discussion] Square Eight
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