Nose weight

[Rcmaster199 at aol.com]

BRAVO!! 
 
The whole point was that it was a simple comparison of densities.  Eventhough 
it sounded alot more difficult than that.
 
MattK
 
In a message dated 3/18/2005 12:29:05 AM Eastern Standard Time,  
bob at toprudder.com writes:

Ok,

Air density(NTP) - helium density(NTP) = 
0.001205 g/cm^3  - 0.000166 g/cm^3 = 0.001039 g/cm^3

So, replacing a volume of air  inside the airplane will
only save approx 1 gram per liter, at  normal
atmospheric pressure.

But, your original question involved  stuffing 15 grams
(mass) of helium into 1000cm^3. At normal  pressure,
you would have only .166g, but you would have to
pressurize it  to stuff the 15g into the stab, and
would end up with 15g of helium instead  of the normal
12g of air. So, to answer your question, 15g of helium
in  the stab would hurt, not help.

Bob R.


 
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