PUZZLE!

[Grow Pattern]

How about you go fly!!!!!!!!!  It's not winter yet....

Evl-one
  ----- Original Message ----- 
  From: Atwood, Mark 
  To: discussion at nsrca.org 
  Sent: Monday, August 15, 2005 4:01 PM
  Subject: RE: PUZZLE!


  DING DING DING.we have a winner. Sort of.     The number is right.meaning that you're taking the size of the sphere as the diameter of the cylinder approaches zero.  

   

  All your missing is the key assumption.that the volume of the remaining material remains constant regardless of the size of the Sphere.which is true.

   

  Now.for the big bonus.do the proof!!!!   (FYI, the proof is a pain)

   


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  From: discussion-request at nsrca.org [mailto:discussion-request at nsrca.org] On Behalf Of Ken Thompson
  Sent: Monday, August 15, 2005 4:01 PM
  To: discussion at nsrca.org
  Subject: Re: PUZZLE!

   

  This is just a wild guess, I'm not real good at these.

   

  If the hole is of a very small diameter that would make the sphere 6 inches in diameter.  

   

  If the sphere is 6" in diameter than the resulting volume would be...4/3 x pi x r cubed  or  113.09733552924001

   

  That's the best I can do on short notice, with my minimal remaining brain cells.

   

  Ken

    ----- Original Message ----- 

    From: Atwood, Mark 

    To: discussion at nsrca.org 

    Sent: Monday, August 15, 2005 3:12 PM

    Subject: PUZZLE!

     

    Ok.this is by no means Airplane related, but it seems to me that with all the engineers that solicit this list-serve, we could have some fun with a few puzzles.  So since it's slow (While we wait for the worlds to start next week) I thought I'd post a fun one.

     

    Imagine a Sphere that has a cylindrical hole bored through the center, the diameter of which results in the remaining hole being 6 inches long.  What is the volume of the remaining material in the sphere??

     

    And yes, you have enough information, and yes, I'm looking for a numerical, absolute answer!!

     

    -Mark
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