Friday Night Masters' Question

[Rcmaster199 at aol.com]

In a message dated 6/20/2003 10:11:03 PM Eastern Daylight Time, 
rcaerobob at cox.net writes:


> Subj:Re: Friday Night Masters' Question 
> Date:6/20/2003 10:11:03 PM Eastern Daylight Time
> From:<A HREF="mailto:rcaerobob at cox.net">rcaerobob at cox.net</A>
> Reply-to:<A HREF="mailto:discussion at nsrca.org">discussion at nsrca.org</A>
> To:<A HREF="mailto:discussion at nsrca.org">discussion at nsrca.org</A>
> Sent from the Internet 
> 
> 
> 
> Great info, and validates what I thought...
>     On the Cuban Eight, however, that's a hair-splitter....because the 
> transition from point to point occupies some distance based on the speed of the 
> roll, and the velocity of the airplane....sooooo....ya better have REALLY, 
> REALLY good eyes to distinguish that....or am I missing something new...??
> 
> Bob Pastorello, Oklahoma
> NSRCA 199, IMAC 1320, AMA 46373
> <A HREF="mailto:rcaerobob at cox.net">rcaerobob at cox.net</A>
> <A HREF="http://www.rcaerobats.net/">www.rcaerobats.net</A>
>  
> 

No I don't think you are missing it. Remember that roll rate must be the same 
in these situations so technically the 1/4 rolling elements should use up the 
same amount of sky (assuming constant model speed--on a downward diagonal, 
that is a good assumption).

The hesitation between the roll elements only needs to be present. 
I think the point is, establish the 45 , 1/4 roll befiore center and hold it 
past center, then 1/4 roll again, and re-establish the 45, then pitch.

I do think we have made the maneuver alot more difficult than it is. 

matt
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